site stats

If 1 is a root of equation ay2+ay+3

Web2 dec. 2024 · Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. If 1 … WebSolve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.

If x = 1 is common root of equations ax^2 + ax + 3 = 0 and x^2

WebUntitled - Free download as PDF File (.pdf) or read online for free. WebSolution: here given equations ay2 + ay + 3 = 0 and y2 + y + b = 0, If 1 is the root of the given equations Then this root will satisfy both the equations On substituting y = 1 in both the equations a(1)2 + a(1) + 3 = 0 and (1)2 + 1 + b = 0 ⇒ a + a + 3 = 0 and 1 + 1 + b = 0 … hotels sherry golf https://agadirugs.com

If 1 is a root of the equation ay² + ay + 3 = 0 and y² + y + b = 0 ...

WebIf x=1 is common root of equations ax 2+ax+3=0 and x 2+x+b=0, then value of ab will be: A 1 B 3.5 C 6 D 3 Medium Solution Verified by Toppr Correct option is D) ax 2+ax+3=0 x=1 is a root of the equation a+a+3=0 2a=−3 a= 2−3 x 2+x+b=0 x=1 is root 1+1+b=0 b=−2 … WebIf 1 is a root of the equation `ay^(2)+ay+3=0" and "y^(2) ... Rated by 1 million+ students Get app now Login. Remember. Register; Test; JEE; NEET; Home; Q&A; Unanswered; Ask a Question; Learn; Ask a Question. If 1 is a root of the equation `ay^(2)+ay+3=0" and "y^(2)+y+b=0` then find the value of ab. WebIf 1 is a root of the equation ay2+ay+3=0 and y2+y+b=0, then find abIf 1 is a root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0, then ab equals.If 1 ... lincoln green south subdivision houston tx

What is the value of M Kite FGHK? – Wisdom-Advices

Category:Doc3 - Copy

Tags:If 1 is a root of equation ay2+ay+3

If 1 is a root of equation ay2+ay+3

If 1 is a root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0 ...

Web2 dec. 2024 · Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. Solution For If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab. If 1 is a root of the equations ay²+ay+3=0 and y²+y+b=0, then find ab... WebIf 1 is a root of the equation a y 2 + a y + 3 = 0 and y 2 + y + b = 0 then find the value of ab. Advertisement Remove all ads Solution It is given that y = 1 is a root of the equation a y 2 + a y + 3 = 0 ∴ a × ( 1) 2 + a × 1 + 3 = 0 ⇒ a + a + 3 = 0 ⇒ 2 a + 3 = 0 ⇒ a = - 3 2 Also, y = 1 is a root of the equation y 2 + y + b = 0 ∴ ( 1) 2 + 1 + b = 0

If 1 is a root of equation ay2+ay+3

Did you know?

WebIf 1 is a root of the equations ay2+ay+3=0 and y2+y+b=0 then ab equals 3 −72 6 -3 The given equations are ay2+ay+3=0 and y2+y+b=0Given 1 is the roots of bo Web23 jan. 2024 · It y=1 is a common root of the equation ay2+ay+3=0 and y2+y+b=0, then ab equals: (a) 3 (b) 2−7 (c) 6 (d) −3 3. If the sum of the roots of the equation x2−x=λ(2x−1) is zero, then λ= (a) −2 4. If one root of the equation 2x2+kx+4=0 is 2 , then the other root is (a) 6 (b) 2 (c) −21 (d) 21 (b) −6 (c) −1 (d) 1 Viewed by: 0 students

WebSolution The given equations are ay2 + ay + 3 = 0 and y2 + y + b = 0 Given, 1 is the root of both the equations. ∴ y = 1 will satisfy both these equations. Putting y = 1 in ay2 + ay + 3 = 0, we get ∴ a × ( 1) 2 + a × 1 + 3 = 0 ⇒ a + a + 3 = 0 ⇒ 2 a + 3 = 0 ⇒ a = - 3 2 ........... (1) … Web3 dec. 2024 · If 1 is root of the equation ay2+ay+3=0 and y2+y+b=0 then ah equals Viewed by: 5,050 students Updated on: Dec 3, 2024 1 student asked the same question on Filo Learn from their 1-to-1 discussion with Filo tutors. 3 mins Uploaded on: 12/3/2024 Taught by Manas Kumar Connect instantly with this tutor Connect now

Web13 nov. 2024 · Given, 1 is the root . so, ay²+ay+3 = 0 a(1)² + a.1 + 3 = 0 (°.° root is 1) => a+ a + 3 = 0 => 2a + 3 = 0 => a = -3/2 again, y²+y+b = 0 => 1 + 1 + b= 0 => 2 + b = 0 => b = - 2 so, we got value of a and b that's why ab = -3/2×-2 = 3 hopes I helped http://svpssadabad.org/documents/cms/1/2_2001131229516_Maths%20X%20Standard%20Sample%20Paper%202.pdf

WebThe answer of your question If 1 is a root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0, then ab equals is : from Class 10 Quadratic Equations. Toggle navigation. NCERT Classes. NCERT Solution For Class 7; NCERT Solution For Class 8; NCERT Solution … lincoln green inn carmel by the seaWebQ.1 of chapter 5, Delhi-2012 - Last Year Paper - Mathematics book. If 1 is a root of the equations ay 2 + ay + 3 = 0 and y 2 + y + b = 0, then find the value of ab. hotels sherman oaks caWebIf 1 is a root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0, then find the value of ab. Root of the Equations: The roots of the equations can be defined as the real... lincoln greenbacks assassinationWeb(1) f(x) 2. If x2_ = 3, then X = (3) f(x)—a 3. If one root of the equation x —px+8=Ois twice the other, then p = — PX + 8 = O p = 4. If x = 2 is one solution of +2x— 3 = O, then the value of k = x = 2 kX2 +2x — 3 = O, k (1) (2) 5. If 1 is a common root of the equations … lincoln greyhound hood ornamentWeb3 mei 2024 · Best answer If y = 1 is root of both the equation it will staify both the equations Putting y = 1 in first equation ay 2 + ay + 3 = 0 2a + 3 = 0 a = −3/2 a = − 3 / 2 Putting value of y in second equation 2 + b = 0 B = – 2 Now ab = − 3 2 = − 3 2 x – 2 ab … lincoln green solicitors reviewsWebRight Answer is: A SOLUTION The given equations are ay2+ay+3 =0 and y2+y+b= 0 Given, 1 is the roots of both the equations Therefore, y =1 will satisfy both these equations. Putting y =1 in ay2+ay+3 =0, we get a(1)2+ax1+3= 0 ∴ a+a+3= 0 ⇒ 2a+3= 0 ⇒ 2a= −3 ⇒ a= −3 2......(1) Putting y =1 in y2+y+b =0, we get (1)2+1+b =0 ∴ 1+1+b= 0 ⇒ … lincoln gregg youngWeb1] if 1 is the root of the equations ay2+ay+3=0 and y2 +y+b=0 then ab = a)3 b) -7/2 c) 6 d)-3. ... 3] if 1/2 is a root of the equation x2 + kx -5/4=0, then value of k= a) 2 b) 1/4 c) -2 d) 1/2. 4]which of the following is not a quadratic equation; a)(x-2) (x+1) =( x-1) (x-3) b) … lincoln green brewery pubs